C code

Modify the C code to add 10 integers instead of 5? (Hint: Avoid using arrays or Loops for this. We’ll be employing those features in a week or so.) Support your experimentation with a screen capture of the new code being executed.

Modify the code you wrote in step 1 to print an additional statement if the sum of the values is negative (Hint: Consider modifying the existing selection statement) Support your experimentation with a screen capture of the new code being executed.

Create a new test table with at least three separate test cases that identify the input and anticipated result for the code you prepared in step 2. // C code

// This program will calculate the sum of 10 integers.

// Date: 26 June 201

#include

int main ()

{

/* variable definition: */

int value1,value2,value3,value4,value5;

float value6,value7,value8,value9,value10,sum;

/* Initialize sum */

sum = 0;

printf(“Enter an Integer or Float for value1\n”);

scanf(“%d”, &value1);

printf(“Enter an Integer or Float for value2\n”);

scanf(“%d”, &value2);

printf(“Enter an Integer or Float for value3\n”);

scanf(“%d”, &value3);

printf(“Enter an Integer or Float for value4\n”);

scanf(“%d”, &value4);

printf(“Enter an Integer or Float for value5\n”);

scanf(“%d”, &value5);

printf(“Enter an Integer or Float for value6\n”);

scanf(“%f”, &value6);

printf(“Enter an Integer or Float for value7\n”);

scanf(“%f”, &value7);

printf(“Enter an Integer or Float for value8\n”);

scanf(“%f”, &value8);

printf(“Enter an Integer or Float for value9\n”);

scanf(“%f”, &value9);

printf(“Enter an Integer or Float for value10\n”);

scanf(“%f”, &value10);

sum = value1 + value2 + value3 + value4 + value5 + value6 + value7 + value8 + value9 + value10;

printf(“Sum is %.1f\n ” , sum );

if (sum >50)

printf(“Sum is over 50\n”);

return 0;

}

Test Case

Input

Expected Output

1

value1=1

value2=2

value3=3

value4=3

Value5=4

Value6=5

Value7=5

Value8=6

Value9=7

Value10=8

Sum=44.0

2

value1=5

value2=10

value3=15

value4=20

Value5=25

Value6=30

Value7=35

Value8=40

Value9=45

Value10=50

Sum=275.0

Sum is over 50.

3

value1=0

value2=-0

value3=0

value4=0

Value5=0

Value6=0

Value7=0

Value8=0

Value9=0

Value10=0

Sum=0

Test 1

Test 2

Test 3

Create your own C code implementation of one of the following mathematical formulas:

a. y = mx + b; (slope of a line) Assume the user will be prompted to input m, x and b and the program will calculate y. If the value of y is greater than 10, inform the user the value is greater than 10.

b. a = PI * r*r; (area of circle). Assume the user will be prompted to input the radius r. You can define PI as 3.1416. . If the value of a is greater than 10, inform the user the value is greater than 10.

c. v = 4/3 PI r*r; (volume of sphere) Assume the user will be prompted to input the radius r. You can define PI at 3.1416. If the value of v is greater than 10, inform the user the value is greater than 10.

Be sure you provide not only the C code but a test table with at least 3 distinct test cases listing input and expected output your mathematical formula.

C Code

// C code

// This program will calculate the slope of a line.

// Date: 22 June 2017

#include

int main ()

{

/* variable definition: */

int m, x, b, y;

/* Initialize calculation */

y = 0;

printf(“Enter an Integer for m\n”);

scanf(“%d”, &m);

printf(“Enter an Integer for x\n”);

scanf(“%d”, &x);

printf(“Enter an Integer for b\n”);

scanf(“%d”, &b);

y = m*x + b;

printf(“Slope of the line is %d\n ” , y );

if ( y > 10)

printf(“the value is greater than 10\n”);

return 0;

}

Test Table

Test Case

Input

Expected Output

1

m = 4

x = 7

b = 3

Y = 20

The value is greater than 10

2

m = -8

x = 4

b = 3

Y = -21

3

m = 0

x = 0

b = 0

Y = 0

Test 1

Test 2

Test 3